I coded the following implementation of lazy sieve algorithms using Stream and lazy val below : def primes(): Stream[Int] = {
I have a ListBuffer. I want to remove all elements that meet a certain condition. I could iterate over it and remove each element. But what doe Scala say about mutating a list that you are iterating
What is the most efficient way to create empty ListBuffer ? val l1 = new mutable.ListBuffer[String] val l2 = mutable.ListBuffer[String] ()
I have a list that has 3 rows each representing a table row: >>> print list [laks,444,M] [kam,445,M]
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