From regular-expressions.info: \\b\\w+(?<!s)\\b. This is definitely not the same as \\b\\w+[^s]\\b. When applied to Jon\'s, the former will match Jon and the latter Jon\' (including the apostroph
Basically, I am changing any and all hexadecimal values with a blue hue to its red hue counterpart in a given stylesheet (i.e. #00f is changed to #ff0000 (my function outputs six character hexadecimal
I\'m having a regex blackout here. How do I capture a negative lookbehind pattern again? I\'m trying to remo开发者_运维百科ve the scheme (including ://) of a uri unless it is http/https. I\'m half wa
I\'m attempting to determine the end of an English sentence (only approximately), by looking for \"!\", \"?\" or \".\", but in the case of \".\" only when not preceeded by common abbreviations such as
I\'m using a regex to find any URLs and link them accordingly. However, I do not want to linkify any URLs that are already linked so I\'m using lookbehind to see if the URL has an href before it.
So, I am doing this search in vim: /\\(\\(unum\\)\\|\\(player\\)=\\)\\@<!\\\"1\\\" and as expected it does not match lines that have:
I have the following regexp: (?P<question>.+(?<!\\[\\[)) It is designed to match hello world! in the string hello world! [[A string typically used in programming examples]]
I\'m trying to grep through a bunch of files in nested subdirectories to look for regular expression matches; my regex requires negative lookbehind.
I want to match every \'[\' or \']\' that\'s not preceded by a backslash in ruby 1.9 I tried: /?&开发者_开发百科lt;!\\134[\\[\\]]/
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