I want the derived class to be a descendant of a template class. That class depends on descendant\'s members.
In C++开发者_开发知识库, the typename keyword is needed so the compiler can disambiguate between nested types and nested values in templates.However, there are certain situations where no ambiguity is
I\'ve been working lately on a small project, and I couldn\'t figure out something.. I\'ve been given a .h file that was containing a class, using a typename template. Inside that class there was a p
I\'m thinking of using the characters #@! in some COM interfaces our system generates. The COM type library is also exported to .NET. Will those characters cause me trouble later on?
As I understand, template aliases in C++0x will allow us to do the following: template <typename T>
i\'m used to write templates like this: template<typename T> void someFunction(SomeClass<T> argument);
template <class T> struct ABC { typedef typename T* pT; }; int main(){} The above piece开发者_StackOverflow中文版 of code gives errors
This question already has answers here: Closed 12 years ago. Possible Duplicate: Officially, what is typename for?
I have a class like this template< typename T > class vector { public: typedef T &reference; typedef T const & const_reference;
跳楼歌作词:崔龙阳作曲:崔龙阳演唱:崔龙阳一个走失的小孩蹲在陌生的天台看着快餐的城市笑起来那里有人在示爱那里有人在使坏那里有人握着手去伤害演说家三个字谁最大你看清吗鱼和虾在污水慢慢地爬我是先喝醉了跳上