When I do: channel = session.query(Channel).options(eagerload(\"items\")).filter(Channel.title == title)
I have two SQLAlchemy model objects designated thus: class SpecInstance(Base): spec_id = Column(Integer, ForeignKey(\'spec.spec_id\'))
Engine = create_engine(\"mysql+mysqldb://blah-blah-blah\", encoding=\"utf-8\") Session = sessionmaker(bind = Engine)
I have a rather complex object that takes a few other objects as its members. Something like this: from engine import engine
Closed. This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing
How can I use ORDER BY descending in a SQLAlchemy query like the following? This query works, but returns them in ascending order:
In this开发者_StackOverflow社区 thread someone pointed me to use sqlalchemy-migrate to help with a fast-changing web application using sqlalchemy.
Newbie question. Pylons 1 + SQLA using declarative style. New to Python. I have a \"master\" class called Entity, which \"child\" classes must belong to for them to be valid. My link to the master cl
The following works s = select([tsr.c.kod])开发者_Python百科.where(tsr.c.rr==\'10\').group_by(tsr.c.kod)
I\'m trying to do something like this: Session.query(some_table).filter(\"/some/path/to/element\".startswith(some_table.path)).all()