I have a system of type traits that resides in a namespace, like so: namespace my_namespace { template <typename T>
Let\'s say I have some templated class depending on type T.T could be almost anything: int, int*, pair <int, int> or struct lol; it cannot be void, a reference or anything cv-qualified though.开
In layman\'s terms, what\'s the difference between trivial types, standard layout types and POD开发者_高级运维s?
this question is related to c++ there is a library which declares a class named Solver < TS,FS >. Solver is a member of another class Domain (written by me)
I just want to know if there is already one provided by the standard. I know it\'s easy to make one yourself
I want to determine if any variadic class template is the base of another class.Typically I\'d use std::is_base_of, but I don\'t think my use case fits, and I\'m not sure if there\'s already something
I want to distinguish between an overloaded member-function in a C++ template struct. The static method get_pointer from specialized struct distinguish_foo should return a pointer to derived::foo if t
template<typen开发者_运维知识库ame T> struct foo { T* p; foo(T* x) : p(x) {} ~foo() { if(p) delete p; }
I want to specialize a class template for char, short, long and long long. This specializations should also holds good for the signed and unsigned variants of the integral types.
What is the proper way to declare the iterator i in the following code? #include <iostream> #include <vector>
加载中,请稍侯......