How do I get the \"dereferenced type\" of another type in C++03?Note that it can be other dereferenceable type like std::vector<int>::iterator.
We\'re not allowed to define a functor struct inside a function because one is not allowed to use function declared structs in the instantiation of function templates.
i am trying to compile my program where i am using the functions like sqrt pow and fab开发者_开发问答s. I do have math.h included but for some reason i get errors like:
This question already has answers here: Closed 11 years ago. Possible Duplicate: Is there an easy way to tell if a class/struct has no data members?
The \"solution\" below compiles but it is not what I want. I would like to pass the put member function to for_each and not *this. Using boost is NOT an option. Can this be solved within C++03?
The new standard has different undefined behavior from the old one. The new sequencing rules, for example, mean that some arithmetic operations that use开发者_运维问答d to be undefined (for such reaso
If you have this function template<typename T> f(T&); And then try to call it with, let\'s s开发者_高级运维ay an rvalue like
If I declare a base class (or interface class) and specify a default value for one or more of its parameters, do the derived classes have to specify the same defaults and if not, which defaults will m
I\'m doing some maintenance work and ran a开发者_运维百科cross something like the following: std::string s;
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