Confused Rails 3 newbie. My model has a purchase_price attribute defined like this: t.decimal :purchase_price, :precision => 12, :scale => 2, :default => 0.00
In Java, new BigDecimal(\"1.0\"开发者_JAVA技巧) != new BigDecimal(\"1.00\") i.e., scale matters.
I always thought you should never use floats for saving m开发者_Go百科oney in the database. So i used decimal. The problem is i save a decimal 100 and it puts it in the database as 99.9999
What would be a good way to trim more than two trailing zeros for a BigDecimal So 1.2200 would print 1.22 and 1.0000 would print 1.00
I have a field as: jFormattedTextFieldGrossWeight = new javax.swing.JFormattedTextField(); jFormattedTextFieldGrossWeight.setFormatterFactory(new javax.swing.text.DefaultFormatterFactory(new javax.sw
scala.math.ScalaNumber is a Java file which looks like this: public abstract class ScalaNumber extends java.lang.Number {
Basically, I\'m curious on how to get hold of new BigDecimal(Double.toString(d)) without going through the process of creating a string.
double radius = 5; double area = Math.PI * Math.pow(radius, 2); // System.out.println(area); BigDe开发者_高级运维cimal bd = new BigDecimal(area).setScale(2, HALF_UP);
I am working with an application that is based entirely on doubles, and am having trouble in one utility method that parses a string into a double.I\'ve found a fix where using BigDecimal for the conv
In java am trying to find an efficient way to round a BigDecimal to two decimals, Up or Down based on a condition.
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