I have an object coming from .Net that has a property of type SyncHashTable that can\'t be viewed w/o an exception being thrown.
Assume I have a class like this: public class Server { public static void main(String[] args) { Map<Integer, ServerThread> registry = Collections.synchronizedMap(new LinkedHashMap<Integer,
I\'ve read many docs about thread states, some of them tells that there is two different states: blocked (before synchronized) and wait (if calls wait), some others are telling that there is only one
I\'m using EclEmma for coverage analysis. My Java code includes a synchronized(MyClass.class) {} block.
I am new to Java and I\'m attending a Concurrent Programming course. I am desperately trying to get a minimal working example th开发者_如何学编程at can help to demonstrate concepts I have learnt like
Java 5 and above only.Assume a multiprocessor shared-memory computer (you\'re probably using one right now).
Does the following variable, x, need to be volatile? Or does the manipulation within a utils.concurrent lock perform the same function as a synchronized block (ensuring it\'s written to memory, and
I am wondering at the difference between declaring a variable as volatile and always accessing the variable in a synchronized(this) block in Java?
I have a manager as Spring wired bean. I believe every bean defined for spring by default is wired as singleton. I have some methods in this bean which I need to synchronize.
I\'m experimenting Java Multi-Threading using synchronization on method comparing with Atomic variables (java.util.concurrent.atomic package).
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