By trie map I mean an associative array, where the payloads are stored in a trie instead of a hash table.
I need a value of Someclass based on the key. And the key can be a string, boolean, or another Object, that\'s why I usedObject as key. But I have a problem, when the object is a string. and I have tw
Is there anyway I can define a sequence/order for all objects in a JVM so that for any two distinct objects o1 or o2, there\'s a well defined rule that says either o1 > o2 or o2 > o1 and o1 == o2 if a
Let\'s say we have a bunch of Car objects. Each Car has some distinguishing properties e.g. manufacturer, model, year, etc. (these can be used to create distinct hashCodes).
I understand why providing same hashcode for two equal (through equals)objects is important. But is the vice vers开发者_运维知识库a true as well, if two objects have same hashcode do they have to be e
I read an algorithm book which stated that the key of a given string is calculated as follows s[0]*31^(n-1) + s[1]*31^(n-2) + ... + s[n-1]
How likely is it to get a HashCode collision with the function below in following scenarios. With random int values for key[0],key[1], key[2], key[3]
The SCJP 6 Study Guide from Bert Bates and Kathy Sierra states on page 554 (among other requirements) that x.hashCode() != y.hashCode() requires that x.equals(y) == false.
So I asked another related question here: java string hash function with avalanche effect, but I have a different, related question now.
To quote from Guidelines and rules fo开发者_运维问答r GetHashCodebyEric Lippert: Rule: Consumers of GetHashCode cannot rely upon it being stable over time or across appdomains
加载中,请稍侯......