If I declare and never use variable then gcc will give me a warning. But if I have a struct with several members and some of those are not used, gcc will not warn about it...
Transitioning from C++, I am now learning the dark art of C and have developed the following code to replace my need for templating.In the bottom example, I have implemented your garden-variety Node s
I\'ve just been bitten by a nasty undefined behavior due the returning a reference to a local variable.
I have to compile a .c file that came with a matlab toolbox. To this end I downloaded xcode 3.1.4, and now I am trying commands like
In a test, I\'m discarding anything from stderr since it clutters the output of the test case. I\'m using the following code:
I am a linux amateur and am trying to build nginx on Debian (Lenny) for the first time. Attemps to build nginx are failing and I receive the known warnings on sys_errorlist and sys_nerr as documente
For instance: Bool NullFunc(const struct timespec *when, const char *who) { return TRUE; } In C++ I was able to put a /*...*/ comment around the parameters. But not in C of course, where it gives me开
I have look-up-table as defined below and I\'m making use of GCC. When I compile I get warnings as warning: braces around scalar initializer
I\'m getting these two warnings (with GCC 4.2 on MacOSX): /Users/az/Programmierung/openlierox/build/Xcode/../../src/main.cpp:154:0 /Users/az/Programmierung/openlierox/build/Xcode/../../src/main.cpp:1
I\'m trying to compile a wireless network card driver for my Linux box and I ran into a problem with the Make command. During the compilation process I norm开发者_运维百科ally see warnings on some of
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