Let\'s say I have a function def odd_or_even n if n%2 == 0 return :even else return :odd end end And I had a simple enumerable array
I\'m very confused about this issue and can\'t understand it.In the Enumerable Documentation, I read this:
k = [1,2,3,4,5] for n in k puts n if n == 2 k.delete(n) end end puts k.join(\",\") # Result: # 1 # 2 # 4 # 5 # [1,3,4,5]
looper = (0..3).cycle 20.times { puts looper.next } can I somehow find the next of 3? I mean if I can get .next of any particular element at any given time. Not just display loop that starts with th
I was helping with an answer in this question and it sparked a question of my own. Pie is an object that has a pieces array made of of PiePiece objects.
I want to be able to have an object extend Enumer开发者_JAVA百科able in Ruby to be an infinite list of Mondays (for example).
when trying to use the Enumerable method on a named query, with a Stateless session, as shown in the example at:
class Foo { public static IEnumerable<int> Range(int start, int end) { return Enumerable.Range(start, end);
In this code, I create an array of strings \"1\" to \"10000\": array_of_strings = (1..10000).collect {|i| String(i)}
I\'m building a widget to show medal counts for the Olympics. I have a collection of \"country\" objects, where each has a \"name\" attribute, and \"gold\", \"silver\", \"bronze\" for medal counts.