I have the following code: #include <conio.h> using namespace std; int _tmain(int argc, _TCHAR* argv[])
In his answer, specifically in the linked Ideone example, @Nawaz shows how you can change the buffer object of cout to write to something else. This made me think of utilizing that to prepare input fr
char word[10]; int n=5; while(n--) { cin>>word; cout<<n<<\" \"<<word<<\" \";
i\'m curently doing a simple program that consists of a while-loop that reads in开发者_如何学运维 two ints and then prints them out. My question is, how can I exit the program when the user inputs the
I have posted the relevant code below. When I compile the program, it runs and reaches the point where it waits for the input. I type in an integer and press ENTER, but the code never continues. How开
In the following code i\'m having trouble with cin.The first cin performs fine, but the second doesn\'t receive input at all.I\'ve tried cin.clear() to clear the input stream, but it doesn\'t help.Whi
I\'ve been assigned a开发者_Go百科 problem I simply do not understand.I know that I need to use a cin function (like cin.get()), but I\'m not sure which one I need or how to use it in this circumstanc
First off my understanding is that cin >> std::noskipws >> str; should stick a whole line from cin like \"i have spaces\" into str.However this only puts \"i\" into str.This could be a
This may at first seem like an odd question, but when a cin request is made, if it receives the wrong type it still continues but the status of cin changes.
I\'m just learning some stuff about cryptography and I made a cool program to encrypt any message by rotating the letters through the alphabet a given number of letters...anyway...I have it all set up
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