Is there any way to squelch the output that glibc generates when there is memory corruption? Here\'s what I\'m seeing
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I am working under Ubuntu 11.04 and now engaged in a project whose source code uses routines like \"sqrtf\" or \"lgamma\", which are 开发者_如何学JAVAcomplained by my IDE, claiming that they cannot be
If the re开发者_JS百科turn value of read() is the same as the buffer size, how do I read the rest of the information? If read is invoked again, will it read the next chunk of data, or read from beginn
I am trying to learn about code vulnerabilities, and am testing some simple programs I wrote.However, many of the issues Glibc catches during runtime (e.g. Stack-S开发者_高级运维mashing, Double Free,
When I disassemble 开发者_开发百科my small function, I happened to see this call call0xf60d2f47 <__i686.get_pc_thunk.bx>.
In the following code I am getting an error: 333glGenBuffers(surftotal, uiVBO); 334{ 335for(surfnum=0; surfnum<surftotal; ++surfnum)
According to section 4.9.6.1 of the C89 draft, %d is a character that 开发者_如何转开发specifies the type of conversion to be applied.
I have this small function that is causing me headaches on RHEL6, and I am not sure what is going on... and it is a pain to debug.开发者_运维百科When I run this I am getting a STORAGE_ERROR, so I did
I have bad shared library (undefined symbol). When I call dlopen() on it the first time, I get a NULL result with correct error message from dlerror().
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