Ok, I think I overcomplicated things and now I\'m lost. Basically, I need to translate this, from Perl to Lua:
I have this sample string : ≪! [If Gte Mso 9]>≪Xml>≪Br /> ≪O:Office Document Set开发者_StackOverflow社区tings>≪Br /> ≪O:Allow Png/>≪
I am working on a VERY simple script to clean up a few hundred thousand small XML files. My current method is to iterate through the directory and (for each file) read the file, use String::gsub! to m
I have text that has these fancy double quotes: \'“\' and I would like to replace them with regular double quotes using Ruby gsub and regex.Here\'s an example and what I have so far:
I am using gsub in Ruby to make a word within text bold.I am using a word boundary so as to not make letters within other words bold, but am finding that this ignores words that have a quote after the
In the following lua co开发者_运维知识库de: function interp(s, tab) return (s:gsub(\'($%b{})\', function(w) return tab[w:sub(3, -2)] or w end))
I have an application which allow user upload documents to Scribd. I tried to use scribd_fu in Rails. An error occurred when the controller try to save the model.
How would I get last 12 digits of a string using mysql? Let\'s say I have a varchar field with a tracking number, that may be anywhere from 5 to 20 varchars long.But I only need to select last 12 dig
I\'m trying to create permalink like behavior for some article titles and i don\'t want to add a new db field for permalink. So i decided to write a helper that will convert my article title from:
Try the following code: s = \'#value#\' puts s.gsub(\'#value#\', Regexp.escape(\'*\'))# => \'\\*\' puts s.gsub(\'#value#\', Regexp.esc开发者_运维知识库ape(\'+\'))# => \'\'
加载中,请稍侯......