I have the following code: #include <iostream> #include <limits> int main() { std::cout << std::numeric_limits<unsigned long long>::digits10 << std::endl;
I have selected columns from a database table and want this data with two decimal places only. I have:
So I\'ve just got a quick question on padding with 0\'s. The examples I made are below, just assumed that length doesn\'t matter and there is no sign bit.
I have a string that starts with a number (from 0-9) I know I can \"or\" 10 test cases using startswith() but there is probably a neater solution
Given a large number, e.g. 9223372036854775807 (Int64.MaxValue), what is the quickest way to sum the digits?
I\'m fairly new to Javascript and have been able to get by so far by just following tutorials and reading forums but this one really stumped me for a while.
Converting non-negative Integer to its list of digits is commonly done like this: import Data.Char digits :: Integer -> [Int]
I found this code for making my textbox only accept numbers. Private Sub TextBox1_KeyPress(ByVal sender As System.Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles TextBox1.KeyPress
Is there any fast way to find the largest power of 10开发者_如何学编程 smaller than a given number?
i want to do what the title says like this: int number1; cin>>number1; num1len=log10(number1)+1; cout<<\"num of digits is \"<<num1len<<\"\\n\";
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