I\'ve sub开发者_开发百科classed UIActionSheet to display a UIPickerView. The idea is the user will select a value from the picker, click Done (a button in a toolbar in the actionsheet). This will pop
In my iOS application, I have a timer firing up, and when it fires, I need to be able to detect whether there\'s an Alert (UIAlertView) or an Action Sheet (UIActionSheet) open.
I need to create a button programmatically just like in the image I know that this is a destructive button in UIActionSheet. Is there any way t开发者_如何学JAVAo use distructive button as a UIButt
I open a UIActionSheet with [actionSh开发者_运维百科eet openInView:view] ... and it opens in the iPhone simulator.And you can\'t click on it.
I have an application which includes a login session. When the application is suspended (iOS 4), I save the current time and if the next time application becomes active is within 15 min from suspensio
I\'m not understanding why this is giving me a EXC_BAD_ACCESS. Basic background, im collecting and processing some information, and then using a modal view to let the user confirm if he want to contin
开发者_高级运维I found in my ipod touch and in iphone simulator, the button \"return\" only respond when touch area inside red rectangle, other places not respond
Apple\'s documentation for the UIActionSheet is causing me confusion. First off, in the iPad Human Interface Guidelines, it says :
I created a UIPickerView inside an UIActionSheet, using the following tutorial: Add UIPickerView & a Button in Action sheet - How?
I\'m implementing a custom URL scheme in my navigation based app to let users import data from an email, and so I have this method in my app delegate:
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