In other words, is there a good reason why this shouldn\'t compile? def f(xs: List[Int]) = xs.foldLeft(0) _// OK
This question already has answers here: Closed 11 years ago. P开发者_如何学Goossible Duplicate: Could anyone explain these undefined behaviors (i = i++ + ++i , i = i++, etc…)
I know about perlop开发者_如何学编程. What I am looking for is a quick lookup like the GHCi :info command:
(First of all this is not HW, I have all the answers) I have a simple BNF grammar <UNIT> ::= ( <CLAUSE> ) | a | b | c
I\'ve got to the section on operators in The Ruby Programming Language, and it\'s made me think about operator associativity. This isn\'t a Ruby question by the way - it applies to all languages.
I am working on the exercise questions of book The Lambda calculus. One of the questions that I am stuck is proving the following:
Why does Prolog match (X, Xs) with a tuple containing more elements? An example: test2((X, Xs)) :- write(X), nl, test2(Xs).
When I type this: puts \'repeat\' * 3 I get: >> repeat repeat repeat But it\'s not working if I do this:
Given the code: my $x = 1; $x = $x * 5 * ($x += 5); I would expect $x to be 180: $x = $x * 5 * ($x += 5); #$x = 1
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