Is it possible, after calling a boost::thread running some instructions, to come back to main thread ?
Do all mutex implementations ultimately call the same basic system/hardware calls - meaning that they can be interchanged?
I have two functions, it used to work for me, I did some changes in the codes but I don\'t know what happened. When I executed those functions as multi-threads, the CPU is 10-30%, and it is so slow. I
According to the draft C++0x standard, this code: void simplethread() { boost::thread t(someLongRunningFunction);
I am writing a small program as part of a University course. In this program, I have a global Boost Mutex which helps me to coordinate two threads.
I\'m implementing a message passing algorithm.The messages propagate through the nodes of the graph, blocking until they have have received enough information (from other neighbours) to send a message
thread_ = boost::thread( boost::function< void (void)>( boost::bind( &clientTCP::run , this ) ) );
I noticed that when I\'m performing a wait operation on a condition variable, it immediately returns. The consequence is that, when executing the following dummy code, 100% of one CPU is being used in
Like conditional signal mechanism, I want one task to wait until some signal is received or some variable becomes true.
So I have code like: using namespace boost::asio::ip; using namespace std; void request_response_loop(boost::asio::ip::tcp::socket& socket)
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