XML parsing in Scala doesn\'t seem to be as easy and straightforward as it should be. What I needed was something that behaved similar to document.getElementsByTagName(name) in JavaScript, but for my
I want to build an web mobile app, and i want to get data from a url, the problem is that url returns a whole webpage..
I\'m parsing the xml on my job. I can\'t change xml creator file untill our other IT group come from holiday. Here is xml file to parse
I\'m trying to speed up my XML parsing and I\'ve stumbled upon Simple XML Serialization which looks pretty good, but I have two questions which I was wondering if anybody could help me with:
I am currently parsing XHTML documents with a DOM parser, like: final Doc开发者_开发百科umentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
I\'m parsing a big XML file using SAXParser in Android and was wondering if there\'s a faster way of doing string comparisons?I\'ve heard rumours that you can use the Dalvik VM to do something which w
How to REALLY remove a node via XMLParser: x=\'\'\'<X> <A> <B c3=\'1\'> <C1>a</C1>
I am working on a ASP.NET site, in which i display results returned by internal search engine to the end user.开发者_如何学Python I am parsing the result creating HTML string to display those results
I am new to the iphone programming. I am using XML Parser to receive the data stored in anNSMutableArray and display it in a TableView.
I\'m trying to fetch XML through this code. NSArray *contacts= [[[[xmlDoc rootElement] elementsForName:@\"contacts\"] objectAtIndex:0] elementsForName:@\"contacts\"];
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