Drupal 6.22 I have an empty page except for a form that takes two input values and, when submitted, must display the result of a query based on that. The result may be displayed in a new window or on
I\'d really appreciate some help with this. I\'m trying to create two different exposed filters in Views. I currently have 6,000 nodes with 75 fields each inside one content type. I\'m using a Page V
How could we display the number of displayed nodes in a View? Like: \"Showing 3842 of 5382 results\" Then if all nodes in the View are displayed at once, (often initially), it might say:
I am working with drupal 7.4, and have installed the Devel module; however, I am missing the \"Enable theme devel开发者_开发知识库oper\" link in its menu.
This query I pulled and worked with from a view. (it is meant to be handed a node id, and return all nodes that have this node id as a node reference)
I am trying to create a very simple page in my module using hook_menu(), but after I test it I get, \"You are not authorized to access this page\". I can\'t figure out what I am doing wrong. Following
This is the issue. I have a block called \'User Favorites Block\' It\'s placed in the region \'First Sidebar\'
I have placed my own php file in /sites/all/modules/开发者_如何学运维<myfolder> and call it via $.post(<myphppage>) from a static html page (javascript function) also in /sites/all/modules/&l
I\'ve just started learning discovering the changes to Drupal 7, and I just found the files[] array now required in the mymodule.info. From what I\'ve found, it is required to add the mymodule.module
I\'m trying to alter the comment links in my Drupal output, and I think I have found the function I want to influence, which is function comment_node_view($node, $view_mode).
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