While reading the description of Functors on this blog: https://hseeberger.wordpress.com/2010/11/25/introduction-to-category-theory-in-scala/
I would like to have a function for either mapping a pure function to a container or sequencing applicative/monadic action through it. For pure mapping we have
I thought I\'d try the intriguing Representable-functors package to define a Monad and Comonad instance for the functor given by data Pair a = Pair a a which is representable by Bool; as mentioned in
Why is the NonEmpty 开发者_Python百科list from the semigroups package not also an instance of the comonad class?It is. The instance is just defined in the comonad package, and not the semigroups packa
I开发者_运维知识库 can define a natural transformation in Haskell as: h :: [a] -> Maybe a h []= Nothing
Who first said the following? A monad is just a monoid in the category of endofunctors, what\'s the problem?
I\'m a bit confused, and need someone to set me straight. Lets outline my current understanding: Where E is an endofunctor, and A is some category:
According to the Typeclassopedia (among other sources), Applicative logically belongs between Monad and Pointed (and thus Functor) in the type class hierarchy, so we would ideally have something like
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