Is there a way to get the current page 开发者_开发知识库URL and all its parameters in a Django template?
I am thinking of a configuration where I have one master website at: www.masterdomain.com and N satelite domains where I can access the satelite domains as follows:
im want to know if there is any way to make a Slug开发者_C百科Field unique for Any field different to pub date?
I have a django app, a forum app, that has templates with it. In those templates, there are urls that point to parts of the app. For instance the thread_list template has links to each thread like so:
My problem is simple,开发者_开发问答 I have an url, I would like to resolve it, but get the url name instead of the view function associated with it ...
I am using Django and I have the following URL in my project\'s urls.py file. (r\'^user/(?P<username>[\\w_\\-\\.]+)/my_app/\', include(\'my_app.urls\')),
Django 1.2 has brought in some changes in the syndication framework. According to this, I sho开发者_如何学JAVAuld now be able to do something like:
I\'m trying to pass a \'string\' argument to a view with a url. The urls.py goes (\'^add/(?P<string>\\w+)\', add ),
First time poster to Stack Overflow... I suspect my answer lies in this solution: Django Query That Get Most Recent Objects From Different Categories
It\'s clear how to create a URLPattern which dispatches from a URL regex: (r\'^books/$\', books), where books can further dispatch on request method:
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