I\'ve got a regular java file that I use to update and query a mysql database but I need to take configurable options in that file (like host name, password, etc) and put it in the web.xml file (or pe
The familiar code: <servlet-mapping> <servlet-name>main</servlet-name> <url-pattern>/*</url-pattern>
When I put these lines: <listener> <listener-class> org.springframework.web.context.ContextLoaderListener
I w开发者_StackOverflowant on all pages BUT ONE (header.jsp) to include-coda like in this code: <jsp-property-group>
Being somewhat lazy, I was rather happy to find that I could create a new servlet source code by going New -> Servlet, instead of going New -> Class and then editing the class into a servlet.
Hello I wish I could define two filters like this <filter-mapping> <filter-name>SecurityFilter</filter-name>
<filter> <filter-name>Acegi Filter Chain Proxy</filter-name> <filter-class> org.acegisecurity.util.FilterToBe开发者_高级运维anProxy
The <display-name> element appears to be a valid sub-element of the <servlet> element as per the Servlet 2.5 deployment descriptor XSD. That is, according to Eclips开发者_Go百科e\'s XML va
This question already has answers here: How can I read context parameter/web.xml values in a non-servlet java file?
In WebSphere Application Server 6.1, is it necessary to redeploy the application (WAR/EAR) every time a change is made to a web.xml de开发者_如何学Goscriptor file?Depends on what you refer to by \"a c
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