In the top-level : unbinded_method = method :puts #=> Object(Kernel)#puts(*arg1) but I did this obj = Object.new
Compiles: public class SerializableObject<T> implements Serializable { public T m_object; } Does开发者_高级运维 NOT compile:
Comparing the following two code snippets: class Logger def self.add_logging(id_string) define_method(:log) do |msg|
Is it possible to get the class name within the body of a class definition? For example, class Foo(): x = magic() # x should now be \'Foo\'
I have two questions regarding the behavior of running the below code. Why is __new__ even being called without instantiating an object? I thought __new__ controlled the creation of a new instance. Ne
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I\'m pretty curious about how this thing works. after require \'sinatra\' then I can invoke get() in the top level scope.
I\'m playing with ruby\'s metaprogramming features, and I\'m finding it a bit hairy. I\'m trying to wrap a method call using a module. Currently, I\'m doing this:
#include <iostream> #include <boost/fusion/mpl.hpp> #include <boost/fusion/include/mpl.hpp>
This question already has answers here: When monkey patching an instance method, can you call the开发者_StackOverflow overridden method from the new implementation?
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