Before a thread can wait on an object, it has to acquire a monitor on that object. The monitor is then released, and the thread attempts to re-acquired it once it awakes.
In Linux kernel, the process descriptor of a process is removed from the system by invoking the release_task() function, after the process has terminated.
I\'m ptrace\'ing a process. After fork/execl and then a wait on the child, I\'m getting a status of 2943. I\'m testing for failure, but waitpid reports non-failure. I\'ve looked in <sys/wait.h>,
If I have a threading.Event and the following two lines of code: event.set() event.clear() and I have some threads who are waiting for that event.
I\'m a n00b to 开发者_StackOverflow社区python, and I\'m looking a code snippet/sample which performs the following:
In one of my methods, I have a toast that appears if the user gives the correct input. However, I do not want the next image to display until the toast has finished.
I am using Selenium2(2.0-b3) web driver I want to wai开发者_如何学运维t for a element to be present on the page. I can write like below and it works fine.
How can I make my thread sleep first before it runs? I know how to get sleep to work, however, whenever my program is run, the thread immediately runs. I want it to WAIT on开发者_如何学Cce it is first
First, this is a near duplicate of: How to differentiate when wait(long timeout) exit for notify or timeout?
When using a wait in an AsyncTask, I get ERROR/AndroidRuntime(24230): Caused by: java.lang.IllegalMonitorStateException: object not locked by thread before wait()
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