In JCR 1 you could do: final InputStream in = zip.getInputStream(zip.getEntry(zipEntryName)); node.setProperty(JcrConstants.JCR_CONTENT, in);
How to obtain File Path/Name from an InputStream 开发者_如何学运维in Java ?It\'s not possible. (not from the FileInputStream in the Java API). The FileInputStream constructor does not store this infor
I\'m attempting to connect two separate applications via a TCP/IP socket. In this case neither of the applications is running as a \"client\" of the other, it would be easier to describe them as two s
I\'m trying to process data obtained from a run of diff to an instance of GNU grep in a java program. I\'ve managed to get the output of diff using the Process object\'s outputStream, but I\'m current
I have to submit code to one of the problems in ACM IPC and, as you may know, the time counts a lot. So, I have to 开发者_StackOverflowread efficiently an input like this:
I\'m doing a simple exercise from a book and I\'m a little bit confused with how the java function parseInt works. I have read a line from an input file, used the StringTokenizer to split it and now I
I\'ve written background InputStream (and OutputStream) implementations that wrap other streams, and read ahead on a background thread, primarily allowing for decompression/compression to happen in di
In pseudocode, here\'s what I\'m doing: Process proc = runtime.exec(command); processOutputStreamInThread(proc.getInputStream());
I\'m trying to build an app to detect images which are advertisements from the webpages. Once I detect those I`ll not be allowing those to be displayed on the client side.
I have a problem that causes all threads in JBOSS to block while reading the input stream. It does not happen predictably and the system can run for days (or longer) before it starts to suffer.
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