I\'m looking for something \"a little bit faste开发者_JS百科r\" than doing SELECT * FROM table_name and stepping through all the records...SELECT COUNT(*) FROM table_name
I have these 2 tables: Table1: CustomerID AreaTypeRevenue 1EuropeInstitutional Clients10 2AsiaInstitutional Clients10
So far I have written Aggregate function followed by Group By c开发者_运维知识库lause to find the values based on SUM, AVG and other Aggregate functions. I have a bit confusion in the Group By clause.
Is it possible to get the sum of a column and all the column itself using one query? I mean, I need SUM(Result.num) and the individual Result.num as well, but I dont want to use two separate queries f
I need to write a sql query on the table such that the result would have the group by column along with the aggregated column with comma separators.
I have a table called testgroup in my database, which is like following: IJ ---------------------- ----------------------
So I have a table of products. Each product has a price (decimal) and开发者_Python百科 quantity (int).
I have a set of tables that I would like to build a view from, for example: Member ID ¦ Name ---¦------
USE AdventureWorks2008R2; GO SELECT SalesOrderID, ProductID, OrderQty ,SUM(OrderQty) OVER(PARTITION BY SalesOrderID) AS \'Total\'
I have a 2-column table named Assignment. The table contains assignment of Person (nvarchar(20)) and Day (date), like here:
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