First of all, I\'m not sure if solution even exists. I spent more than a couple of hours trying to come up with one, so beware.
I\'m trying to write a 4 x 4 grid using verti开发者_如何转开发cal bars and underscore. I have a class for the puzzle, but i want to know what fields and methods i can use to represent and manipulate a
We have a collection of sets A_1,..,A_n. The goal is to find new sets for each of the old sets. newA_i = {a_i in A_i such that there exist (a_1,..,a_n) in (A1,..,An) with no a_k = a_j for all k and j
Let\'s say I want to find all sets of 5 single-digit, non-repeating numbers that add up to 30... I\'d end up with [9,8,7,5,1], [9,8,7,4,2], [9,8,6,4,3], [9,8,6,5,2], [9,7,6,5,3], and [8,7,6,5,4]. Each
Check out the following snippet of HTML/Javascript code: <html> <head> <script type=\"text/javascript\">
In his book programming in scala (Chapter 5 S开发者_运维问答ection 5.9 Pg 93) Odersky mentioned this expression \"bills !*&^%~ code!\"
Given a word jumble (i.e. ofbaor), what would be an approach to unscramble the letters to create a real word (i.e. foobar)? I could see this having a couple of approaches, and I think I know how I\'d
I\'m interested making an implementation of the 14-15 puzzle: I\'m creating an array with the values 0 - 15 in increasing order:
This is not homework. I saw this article praising Linq library and how great it is for doing combinatorics stuff, and I thought to myself: Python can do it in a more readable fashion.
I came across this question: say given two weights 1 and 3, u can weigh 1,2 (by 3-1),3,4 (by 3+1) (using both sides of balance). Now find the minimum number of weights so that you can measure 1 to 100
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