Hi开发者_JAVA百科i... When I tried to validate zend form using ini file, I am getting the following error message, please help how to fix this
I have a controller named class TestControl开发者_如何学运维ler which extends some Zend_Controller_Action. Now I would like to use create an instance of TestController in TestForms (a Zend_Form). I wa
I am able to print the form content in the controller file, but when I assign the form view as $this->view->form = $form and trying to display the form design using echo $this->form in login开
I assigned $this->view->form = $form (form instance) and now trying to display the content in layout.phtml using
HI I开发者_如何学运维 am trying to get the view using the following: $this->getView()->form = $form;
This question already has an answer here: Closed 11 years ago. Possible Duplicate: Need to change smarty file into zend file
How do I submit a Zend开发者_JAVA百科 form using ajax request with jquery so that the page does not refresh? I\'ve used ajaxLink with Zend but I don\'t see how I can use it with a form..Well, I don\'t
i have 4 subforms in a form i would like to group 2 of them together, and then apply some decorators to them.
In this book (the link goes to the part I\'m interested in) it is suggested that you could use a single instance of Zend_开发者_运维百科Form to put both Model and View validations. I\'m wondering exac
I am trying to upload a picture. I have Form_Zend and I use: $image = new Zend_Form_Element_File(\'image\');
加载中,请稍侯......