public class A { public void test(Integer i) { System.out.println(\"In Wrapper Method\"); } public void test(int i) {
I need a map where the values are of different types, like integer, string etc. The problem with Java is that primitives here are not Objects which suggests that it may not be possible to have a hybri
Right now, i have this: // .h - (NSArray *)createNumberArrayWithInts:(NSInteger)firstArg, ... NS_REQUIRES_NIL_TERMINATION;
How can I pass a primitive type by reference in java? F开发者_如何学JAVAor instance, how do I make an int passed to a method modifiable?There isn\'t a way to pass a primitive directly by reference in
I\'m new to Java but if I understand correctly, a char is a primitive. Doing char temp and temp.hashCode() won\'t compile but doing a char[] temp2 = new char[2]开发者_JAVA技巧 and temp2.hashCode() wi
With autounbox开发者_高级运维ing, this statement will automatically work: int myPrimitive = (Integer) doIt();
I am fairly new to C# coming from Java, and I\'m wondering if there\'s a simple way to avoid code repetition involving primitive types like this:
Why is string a reference type, even though it\'s normally 开发者_如何学运维primitive data type such as int, float, or double.In addition to the reasons posted by Dan:
I have just started reading through The C Programming Language and I am having trouble understanding one part.Here is an excerpt from page 24:
Probably a simple question: Why do I get an compiler warning for the following objective-C code? //_classificationView.tag is a NSString
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