This question already has answers here: sizeof single struct member in C (9 answers) 开发者_StackOverflow中文版
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical andcannot be reasonably answered in its current form. For help clari
It\'s trivial to get the size of a struct\'s field in C++ if you have an instance of the struct.E.g. (uncompiled):
I don\'t understand why struct e{ void * a; void * b[]; } has sizeof(e) == 4 while struct f{ void * a; void * b;
Given: templ开发者_开发技巧ate <int N> struct val2size { char placeholder[N]; }; Is there any guarantee that sizeof(val2size<N>) == N?The only guarantee is that
This may be a stupid ques开发者_运维技巧tion but how does the sizeof operator know the size of an array operand when you don\'t pass in the amount of elements in the array.I know it doesn\'t return th
So, a couple of questions, actually: An int (Int32) is specified to be (obviously) 32 bits. What about an int? (Nullable<int>)? My gut tells me that it would be 32 bits for the integer plus 8
gcc 4.4.3 c89 I am wondering why I can\'t allocate the size of开发者_如何学Go the array when initializing an array of pointers to char.
(sizeof) char always returns 1 in 32 bit GCC compiler. But since the basic block size in 32 bit compiler is 4, How does char occupy a single byte when the basic size is 4 bytes???
typedef struct BaseMessage { int u32DeviceID : 32; int u32CoreID : 32; unsigned int u16Class : 16; unsigned int u8OpCode : 8;
加载中,请稍侯......