I am reading Modern C+开发者_JAVA百科+ design. It was mentioned about sizeof opeator as following description. Following paragraph is explained from generic programming point of view.
I\'m working on an open-source project, and there is an hash_table that I need to change for a more efficient hash_table, so, I\'m trying
Size of char, signed char and unsigned char is defined to be 1 byte, by the C++ Standard itself. I\'m wondering why it didn\'t define the sizeof(bool) also?
For unpacking complex binary strings with mixed doubles and integers using Ruby\'s String.unpack I need to determine offsets within the binary string. Commonly, doubles are 8 bytes and integers are 4
In C Programming language and I use 32 bit system, I have a struct and this开发者_运维技巧 struct size is multiple of four.
#include \"usefunc.h\" //don\'t worry about this -> lib I wrote int main() { int i; string given[4000], longest = \"a\"; //declared new typdef. equivalent to 2D char array
In recent I was attend one Interview on \"SureSoft Technology\"...... In that interview, they ask one question lik \"What is size for the sizeof operator in c? \"
I can\'t find an answer in the standard do开发者_开发知识库cumentation. Does the C++ language standard require sizeof(bool) to always be 1 (for 1 byte), or is this size implementation-defined?sizeof(b
The following C program: #include <stdio.h> int main(void) { printf("%u %u %u\\n",sizeof "",sizeof(""+0),sizeof(char *));
Let\'s say I have an array arr. When would the following not give the number of elements of the array: sizeof(arr) / sizeof(arr[0])?