I ran this sample program. const int x = 5; int main(int argc, char** argv) { int x[x]; int y = sizeof(x) / sizeof(int);
I\'d like to know the size of a float in GCC, without having to run the compiler. I know one option is to write a small function and have the compiler print out an assembly listing.
I am hoping that someone can explain the following behaviour. Suppose I am trying to implement a function which determines the length of any array, but want to avoid using macros. For e.g
I\'m trying to write a function that will print out the contents of a multidimensional array. I know the size of the columns, but not the size of the rows.
The definition of GUID in the windows header\'s is like this: typedef struct _GUID { unsigned long Data1;
Looking at this table describing the data types in VB. One of the columns is labeled \"Nominal s开发者_如何学Pythontorage allocation\".What does this mean?Why is the word \"nominal\" here?I believe t
Can anyone explain to me what is going on here? First off, I think most programmers know that a class with a virtual function has a vtbl and thus has 4 extra bytes on the top of it. As far as I know,
I would like to do the following, but the compiler doesn\'t like it: unsigned short foo = 1; // do something with foo
I need to store two items per array element — two arrays of char, which might contain null bytes — and then still be able to use sizeof() to get their length.Since these values will not ch
I have learnt that when we pass the array name to sizeof, the name of the array does not decay to the pointer to base address. The code below verifies this fact by giving answer 10.
加载中,请稍侯......