Saw piece of code in book: 开发者_StackOverflowT& operator[](int i) throw(RangeError) { if(i >= 0 && i < sz) return ptr[i];
Why do the following lines of code not create a compiler warning? void Main() { throw new Exception(); throw new Exception();
I want to build a class with functions that may throw exceptions that I want to catch when I use it. I inherit my_exception from the standard exception class.
I have a question: 开发者_开发知识库how do I throw an exception and exit the program? I have writen down a simple example:
I am trying unsuccessfully to throw an exception TooLongEx if a user input fails. Been stuck on this forever :(
This question already has answers here: Closed 11 years ago. Poss开发者_如何学Goible Duplicate: how to use Java-style throws keyword in C#?
Conventional wisdom says you can o开发者_StackOverflow社区nly throw objects that extend Throwable in Java, but is it possible to disable the bytecode verifier and get Java to compile and run code that
Below, why doesn\'t Throw maintain my originating line number? If I run the DerivedPage, my log file lists the error as line 7.
I am trying to define a really simple exception class. Because it is so simple I want to keep it in the .h file only, but the compiler doesn\'t like throw(). The code:
These days, I have been reading a lot the C++ F.A.Q and especially this page. Reading through the section I discovered a \"technique\" that the author calls \"exception dispatc开发者_运维技巧her\" th