I get a StackOverflowException wh开发者_StackOverflow社区en I run the following code: private void MyButton_Click(object sender, EventArgs e) {
How to declare a pointer to function in C, in order that the pointer itself is volatile. static void volatile (* f_pointer)(void*);
The following excerpt from the current draft shows what I mean: namespace std { typedef struct atomic_bool {
We use volatile in one of our projects to maintain the same copy of variable accessed by different threads. My question is whether it is alright to use volatile with static. The compiler does not give
class MyClass { int x, y; void foo() volatile { // do stuff with x // do stuff with y } }; Do I need to declare x and y as volatile or will be all member variables treated as volatile a开发者_运维技
I\'m reading a book which says not to use such a code: private volatile Thread myThread; .... myThread.stop();
I have an abstract base class class Map { public: virtual Value get(Key const &) const; }; a database class from an external library
UPDATED: now using a read-only collection based on comments below I believe that the following code should be thread safe \"lock free\" code, but want to make sure I\'m not missing something...
I use a mmap\'ed file to share data between processes. The code is like this: struct Shared { int Data; };
In Java, I understand that volatile keyword provides visibility to variables. The question is, if a variable is a reference to a mutable object, does volatile also provide visibility to the members in
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