I\'m attempting to eliminate left recursion from a CFG by eliminating indirect recursion then direct recursion as this algorithm shows.
I have to determine whether a language (for example L={a^n b^m c^s | 0<=n<=m<=s}) is regular, context-free, recursive, recursively enumerable or none of them.
Based on my experience, formal grammars typically express comma-delimited lists in a form similar to this:
Suppose I try to parse a string abc with a Packrat Parser: lazy val abc: PackratParser[AnyRef] = ab ~ \"c\"
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I am working on a Dutch corpus and I want to know if NLTK has dutch grammar embedded in it so I can parse my sentences? In general does NLTK only work on English? I know that it has the Alpino dutch c
ex. S-> S + T | 开发者_如何学PythonT T-> U - T | U U -> ID | N associativity is obviously not preserved.But I can\'t see it being ambiguous in anyways.. So is this a non-ambiguous cfg?A grammar ca
S -> aB | lamda B -> bB B i开发者_如何学Pythons a useless production. Now after its removal
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What class of languages do real modern regexes actually recognise? Whenever there is an unbounded length capturing group with a back-reference (e.g. (.*)_\\1) a regex is now matching a non-regular la
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