Here\'s my code: import urllib2.request response = urllib2.urlopen(\"http://www.google.com\")开发者_高级运维
I\'ve written a Python application that makes web requests using the urllib2 library after which it scrapes the data. I could deploy this as a web application which means all urllib2 requests go throu
I have following code. req = urllib2.Request(url,\'\',txheaders) f = urllib2.urlopen(req) data = f.read(开发者_Go百科)
I\'m using the timeout parameter within the urllib2\'s urlopen. urllib2.urlopen(\'http://www.example.org\', timeout=1)
I have an app that makes a HTTP GET request to a particular URL on the internet. But when the network is down (say, no public wifi - or my ISP is down, or some such thing), I get the following traceba
I\'m using urllib2 to open a url. Now I need th开发者_开发技巧e html file as a string. How do I do this?In python3, it should be changed to urllib.request.openurl(\'http://www.example.com/\').read().d
I can get the html page using urllib, and use BeautifulSoup to parse the html page, and it looks like that I have to generate file to be read from BeautifulSoup.
I found that you can\'t read from some sites using Python\'s urllib2(or 开发者_JAVA百科urllib). An example...
I am using the urllib2 module in Python 2.6.4, running in Windows XP, to access a URL. I am making a post request, that does not involve cookies or https or anything too complicated. The domain is red
I need to download a CSV file, which works fine in browsers using: http://www.ftse.com/objects/csv_to_csv.jsp?infoCode=100a&theseFilters=&csvAll=&theseColumns=Mw==&theseTitles=&t
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