I\'m attempting to implement quicksort in java in order to count the number of comparisons made, but I\'m running into an infinite loop/recursive call situation, and I can\'t quite figure out where it
I want to implement this quicksort algorithm with some different pivot strategy but there is some logical error in it. Can you please help me find it?
As we can choose median of 3 element partitioning to implement quick so开发者_Go百科rt. Likewise can we choose median of 5, 7, or 11 element to implement quick sort? If so, then how??You should look i
I\'ve tried a bunch of different ways to write this, but mostly i get stuck in an endless loop. This version of the code just doesn\'t sort it at all and i don\'t know what the problem is.
I don\'t really understand why we don\'t just always select the median element as the pivot. This can be done in O(n) and thus results in a to开发者_StackOverflow社区tal run time of O(n log n).
I used the quicksort algorithm to sort 11 8 9 4 2 5 3 12 6 10 7 and I got the list: 4 3 2 5 9 11 8 12 6 10 7.
I\'m working on a quicksort problem for arrays of only increasing integers. The pivot choice in this routine is always the first element of the subarray (as dictated by the problem), and at a certain
I read the following in a forum : Merge sort is very efficient for immutable datastructures like linked
When given an array of elements, how can I count the amount of element comparisons the algorithm performs?
I want to be able to take this quick sort 开发者_如何学Goand make it so that the odd numbers are listed in the original order and the even are listed in the original order, but with odd numbers first
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