All, I have been beating my head against the wall for two days on this one. I have googled and googled and I can\'t seem to find a solution. Here is what I have:
I have a dataframe (df1) like this. f1f2f3f4f5 d110111 d210010 d300011 d401001 The d1...d4 column is the rowname, the f1...f5 row is the columnname.
I have 3D matrix (10000 x 60 x 20) and I need to permute 2nd and 3rd dimensions keeping the columns intact.
I have a table with: ID | NAME | CLASS ------------------ 1| Aaa| 1 2| Bbb| 1 3| Ccc| 1 4| Ddd| 1 And so on ...
i got a bit of a problem. I\'ve got an input: \"/0-9/0-9/0-9/0-9\". in this case its 10^4 possibilities.
I\'m looking at Pavel\'s solution to Project Euler question 24, but can\'t quite work out how this function works - can someone explain what it\'s doing? Its purp开发者_高级运维ose is to return the mi
Yesterday I spent the entire day trying to solve a problem that wants me to get the k-th permutation or unrank a permutation.
I have the below input PlayerIDMatchPlayed RunsMade ------------------- -------- 110200 25100 3824 43050 The output will be
Thank you for your help yesterday and for teaching me something new as well. :) I have another question based on permutation... the algorithm I have works however I have the开发者_StackOverflow中文版
permutation([], []). permutation(L, [X|Xs]) :- select(X, L, Rest), permutation(Rest, Xs). If I type permutation([1,2,3],R), the first solution is \"[1,2,3]\" but how to get to the second one without
加载中,请稍侯......