What is happening when a java.lang.Double object is initialized without using a call to the constructor but instead using a primitive?It appears to work but I\'m not quite sure why.Is there some kind
Assigning values without using usual notation like \"this.<D开发者_Python百科ouble>getAnything(int flag)\"
The following code throws NullPointerException: int num = Int开发者_运维问答eger.getInteger(\"123\");
I just saw开发者_StackOverflow中文版 code similar to this: public class Scratch { public static void main(String[] args)
Reference: http://java.sun.com/j2se/1.5.0/docs/guide/language/autoboxing.html \"If your program tries to autounbox null, it will throw a NullPointerException.\"
Can someone explain to me the usage of Integer, Boolean etc in place of their primitive types in JAVA?
Consider the following snippet: int i = 99999999; byte b = 99; short s = 9999; Integer ii = Integer.valueOf(9); // should be within cache
Thanks to the implicit casting in compound assignments and increment/decrement operators, the following compiles:
Autoboxing is rather scary.While I fully understand the difference between == and .equals I can\'t but help have the follow bug the hell out of me:
I was doing one of these online Java tests and I was asked this question: Q: Indicate correct assignment:
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