I have tried: echo -e \"开发者_运维知识库egg\\t\\t\\t salad\" | sed -E \'s/[[:blank:]]+/\\t/g\'
I have lines a开发者_如何学JAVAs this ATOM21001O WAT3457.55635.95437.4640.000.00 ATOM21002H1 WAT3457.07635.70136.6750.000.00
I have some expressions of the form 3*(item1; item2; item3;), and I want to replace them with item1;item2;item3;item1;item2;item3;item1;item2;item3; (i.e. 3 lots of the thing in brackets, not includin
I have a requirement to search for a pattern which is something like : timeouts = {default = 3.0; }; and replace it with
How do I remove the first and the last quotes? echo \"\\\"test\\\"\" | sed \'s/\"//\' | sed \'s/\"$//\'
I\'m trying to replace all occurrences of -> with .. I开发者_如何学C\'ve tried the following:
I have a log file full of queries, and I only want to see the queries that have an error.The log entries look something like:
Still dealing with quirky files (see my pre开发者_如何学编程vious post), I am using SED to cleanup some that are laid out like so:
so, I\'开发者_运维百科ve adduser\'ed micronxd. I\'ve passwd\'d micronxd. now I wanna make micronxd a sudo user.
I need to process a text file. Need to move the chunk of text between the first pattern pair into the second pattern pair (above whatever was already there between the second pattern pair.