class base {}; class der : public base{}; der d1; der d2(d1); This statement invokes default constructor of class base then copy constructor of claas der.
When is a class implicitly copied in C++? I have a class that contains a unique_ptr, and therefore cannot be safely copied, and therefore, I disabled the copy constructor on the class by creating pr
This follows on from my previous question, where I was slow to supply all the information so I am creating a new question in the hope of more input. Given:
This question already has answers here: 开发者_JAVA技巧 Closed 11 years ago. Possible Duplicate: Why should the copy constructor accept its parameter by reference in C++?
I\'m getting a segmentation fault which I believe is caused by the copy constructor. However, I can\'t find an example like this one anywhere online. I\'ve read about shallow copy and deep copy but I\
In VS 2010 SP1, the following: class Foo { public: Foo() { } Foo(Foo const&) = delete; // Line 365 Foo& operator=(Foo const&) = delete; // Line 366
This question already has answers here: 开发者_JAVA技巧 Closed 11 years ago. Possible Duplicates: Why copying stringstream is not allowed?
Here\'s my code: struct RS_Token { char id; char cleanup; unsigned char array[sizeof (std::string) > sizeof (double) ? sizeof (std::string) : sizeof (double)];
Is it possible to \"add\" to the default copy constructor? Eg. For this class: class A { public: int a; int* b;
Why do people define a private copy constructor? When is making the copy constructor and the assignment operator private a good design?
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