What is the best method to replace sequence of bytes in binary file to the same length of other bytes? The binary files will be pretty large, about 50 mb and should not be loaded at once in memory.
I would like to change the license text appearing at the top of hundreds of source files. What is the easiest way of doing this?
I have a input dataframe like this (the real one is very large, so I want to do it faster): df1 <- data.frame(A=c(1:5), B=c(5:9), C=c(9:13))
I am looking to edit XML files using python. I want to find and replace keywords in the tags. In the past, a co-worker had set up template XML files and used a \"find and replace\" program to replace
Search and repl开发者_如何学运维ace over multiple files is difficult in my editor. There are plenty of tricks that can be done with find, xargs and sed/awk incluing search-and replace in multiple file
I have what I thought would be an easy 开发者_如何学编程problem to solve but I am not able to find the answer to this.
In some forum I join, they just replace some link with something like spam or deleted. Example:开发者_开发技巧 www.rapidshare.com/download/123 will automatically turn to www.spam.com/download/123 OR w
x.replace(/old/gi. \'new\'); x.replace(/whatever/gi. \'whatevernew\'); x.replace(/car/gi. \'boat\'); Is there a way to combine those in one regexp st开发者_如何学编程atement perhaps and array of old
I have a string in which I need to replace markers with values from a dictionary. It has to be as efficient as possible. Doing a loop with a string.replace is just going to consume memory (strings ar开
I have gotten comfortable using expressions in Vim to do replaces across large files and would like to know what utility program to learn that will allow me to do such a thing across folders of files
加载中,请稍侯......