Premise I know that writing code to act differently when a test is run is hilariously bad practise, but I may\'ve actually come across a scenario in which it may be necessary.
I\'m new to Unit Testing, and I\'m only getting into the routine of build开发者_开发知识库ing test suites. I have what is going to be a rather large project that I want to build tests for from the sta
I\'m still new to Unit testing, and specifically PHPUnit as the testing framework. Suppose I\'m building a unit test for a resource loader class. The class looks for resources to load in two director
I have an application with the default directory structure, for an application without custom modules (see structure figure at the end).
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I\'m using Zend_Test_PHPUnit_ControllerTestCase to test my controllers. This class provides various ways to test the rendered output, but I don\'t want to get my view scripts involved. I\'d 开发者_C百
I\'m building unit tests for class Foo, and I\'m fairly new to unit testing. A key component of my class is an instance of BarCollection which contains a number of Bar objects.One method in Foo itera
When in PHPUnit test fails, actual and expected values are displayed. But when the test passes, this information is开发者_高级运维 not displayed.
In the xdebug code coverage, it shows the line \"return false;\" (below \"!$r\") as not covered by my tests.But, the $sql is basically hard-coded.How do I get coverage on that?Do I overwrite \"$table\
I have a directoy structure, and all the classes of the business logic are placed in the app_dir/lib/ directory. I would like to generate unit tests for all the classes from this lib/ folder.
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