I have this statement: Assume the bit value of byte x is 00101011. what is the result of x>>2? How can I开发者_如何学C program it and can someone explain me what is doing?Firstly, you can no
I was recently asked a question, \"how do you multiply without using the multiplication operator, without any sort of looping statements or explicit addition\" and realized I wasn\'t familiar with bit
How exactly do the following lines work if pData = \"abc\"? pDes[1] = ( pData[0] & 0x1c ) 开发者_开发问答>> 2;
Alright, Here\'s the gist of what I\'m planning to do. I\'m going to have two tables.One with \"ranks\" or \"roles\" and one with users.I want to assign permissions on a role/user basis and retract p
Original question changed. I want to bitwise turn off the left most bit of a Short value (&H8000) and leave the other bits as they are.
I have a lot of domain entities (stored in mysql) which undergo lots of different operations. Each operation is executed from a different program. I need to keep (flow)-state for these entities which
I am facing a rather peculiar problem. I am working on a compiler for an architecture that doesn\'t support bitwise operations. However, it handles signed 16-bit integer arithmetics and I was wonderin
I have a fragment of bytes in a byte[]. The total size of the array is 4 and I want to convert this into a positive long number. For example if the byte a开发者_开发问答rray is having four bytes 101,
When interviewing new candidates, we usually ask them to write a piece of C code to count the number of bits with value 1 in a given byte variable (e.g. the byte 3 has two 1-bits). I know all the comm
Can you please explain the below lines, with some good examples. A left arithmetic shift by n is equivalent to multiplying by 2n
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