I would like to perform the division of num by 60 which is not power of two using right shift operation. How do I do this?
I haven\'t heard of any, most languages seem to just have division of ints round or be a floating point numb开发者_运维知识库er. Was it found to be a problem in scheme and so not used in other languag
When I make a division in C#, it automaticaly rounds down. See this example: double i; i = 200 / 3; Messagebox.Show(i.ToString());
7/2 = 3.5 How do I get high number of t开发者_运维问答he remainder? In this example it should be 4, not 3.You are looking for the Math.ceil function:
I was working on something else, but everything came out as zero, so I made this minimalistic example, and the output is still 开发者_JAVA技巧0.
This question already has answers here: Why do the division (/) operators behave differently in VB.NET an开发者_如何学God C#?
This is probabl开发者_如何学Goy a simple question, but I a variable \"side\" to be divided by the square of the variable \"curNum\". Currently, my code for this looks like
NASM manual says on DIV: For DIV r/m32, EDX:EAX is divided by the given operand; the quotient is stored in EAX and the remainder in EDX.
I could see in Timesta开发者_运维技巧mp class, the constructor goes like: public Timestamp(long time) {
How does one 开发者_如何转开发divide numbers but exclude the remainder in PHP?Just cast the resulting value to an int.
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