Let\'s try this 开发者_StackOverflow: float test = 3.56; float roundedVal = round(test * 10.0f) / 10.0f;
In order to sync my iPod and my local music repository, I created a unique key for each track using its metadata. The unique track consists of the track\'s following metadata fields:
What would be an elegant, efficient and Pythonic way to perform a h/m/s rounding operation on time related types in Python with control over the rounding resolution?
I can\'t achieve r开发者_JAVA技巧ounding a float. Those calls all returns me 3.5999999 and not 3.6 for theoTimeoutTrick and theoTimeout.
In Xcode /Objective-C for the iPhone. I have a float with the value 0.00004876544. How would I get it to display to two decimal places after the first significant number?
I have a variable, tauMax, that I want to round up to the nearest power of ten(1, 10, 100, 1000...). I am using the below expression to find the closest integer to the max value in the tau array. I am
I\'ve been searching for quite awhile and can\'t seem to find anything on this. How do I round a number up to the nearest whole number? I\'m using the number of objects in an array and dividing it by
I have an interesting issue where I need to round the result of an AVG() function in a specific manner for use in the ORDER BY clause.
I have a floating point number that have more decimal digits, for example: float fRes = 10.0 / 3.0; actually the fRes value is 3.3333333333333
I have an API call which returns a double. The double\'s decimal length can variate from many decimal places to a few (it all comes down to the state of an actuator). This double represents the curren
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