Floating point values are inexact, which is why we should rarely use strict numerical equality in comparisons. For example, in Java this prints false (as seen on ideone.com):
Say I have two Python floats a and b, is there an easy way to find out how many representable real numbers are between the two in IEEE-754 representation (or whatever representation the machine used i
Follow-Up available: There\'s a follow-up with further details, see Convert MBF to IEEE. I\'ve got some legacy data which is still in use, reading the binary files is not the problem, the number fo
This question already has answers here: Closed 12 years ago. Possible Duplicate: What is faster/prefered memset or for loop to zero out an array of doubles
Let\'s say I have this: float i = 1.5 in binary, this float is represented as: 0 01111111 10000000000000000000000
In most cases, I understand that a floating point comparison test should be implemented using over a range of values (abs(x-y) < epsilon), but does self subtraction imply that the result will be ze
Before .Net, before math coprocessors, before IEEE-574, Microsoft defined a bit pattern for floating-point numbers. Old versions of the C++ compiler happily used that definition.
EDIT: I had made a mistake during the debugging session that lead me to ask this question. The differences I was seeing were in fact in printing a double and in parsing a double (strtod). Stephen\'s a
Is converting Fixed Pt. (fixed n bit for fraction) to IEEE double safe ? ie: does IEEE double format can represent all numbers a fixed point can represent ?
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