Have a look at this snippet in Java: double alpha = alphaFactors.get(0, q); double beta = betaFactors.get(0, q);
Why does the following code behave as it does in C? float x = 2147483647; //2^31 printf(\"%f\\n\", x); //Outputs 2147483648
I am testing IEEE 754 floating format with VS2008 using the example below: int main(int argc, char *argv[])
I am trying to convert an 80-bit extended precision floating point number (in a buffer) to double. The buffer basically contains the content of an x87 register.
Question In Haskell, the base libraries and Hackage packages provide several means of converting binary IEEE-754 floating point data to and from the lifted Float and Double types. However, the accura
My method is as follows def myMethod(myDouble: Double): Double = myDouble match { case Double.NaN => ...
Monniaux\'s 开发者_开发技巧excellent article, \"The Pitfalls of Verifying Floating Point Arithmetic\", gives examples of unexpected numerical behavior. However, most of the examples depend on extended
No, this is not another \"Why is (1/3.0)*3 != 1\" question. I\'ve been reading about floating-points a lot lately; specifically, how the same calculation might give different results on different arc
As per the float and real (Transact-SQL) float is an approximate data type. But also in the same article it is being mentioned that float has precision of 15 digits.
Is there any standard method in java to convert IBM 370(in the form of bytes) to IEEE format.?Any algorithm for the conversion would help..
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