this is my working code: while ($list = mysql_fetch_assoc($result)) { $sql2开发者_JAVA百科 = \"SELECT * FROM stock WHERE gID=\".$list[\'gID\'];
This question already has answers here: Closed 11 yea开发者_C百科rs ago. Possible Duplicate: Merge arrays (PHP)
As it currently stands, this questio开发者_如何学Gon is not a good fit for our Q&A format. We expect answers to be supported by facts, references,or expertise, but this question will likely so
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